A car’s initial velocity is 50.0 km/h in the direction 60.0° north of east, and its final velocity is 70.0 km/h in the direction 40.0° south of east. If the time period for this journey is 30.0 minutes, what is the magnitude of the car’s average acceleration?

Answer 1

a=(vf-vi)/time
There are a number of ways to change the vectors, I recommend you break each up into N, and E components, then solve acceleration in N, and acceleration in E, then add them.
the magnitude of average acceleration will be sqrt (a_north^2 + a_east^2)

Answer 2

I DONT UNDERSTAND D QT