A carry-on suitcase is 9.5 inches long, 16 inches wide, and 22.5 inches high. What is the surface area of the suitcase?

(1 point)
O 1, 451.5 in.
2
• 96 in?
• 725.75 in.
2
• 3,420 in.

1 answer

To find the surface area of a rectangular suitcase, we can use the formula for the surface area of a rectangular prism:

\[ \text{Surface Area} = 2(lw + lh + wh) \]

where:

  • \( l \) is the length,
  • \( w \) is the width,
  • \( h \) is the height.

Given the dimensions:

  • Length \( l = 9.5 \) inches,
  • Width \( w = 16 \) inches,
  • Height \( h = 22.5 \) inches.

We will calculate:

  1. Calculate \( lw \): \[ lw = 9.5 \times 16 = 152 \text{ in}^2 \]

  2. Calculate \( lh \): \[ lh = 9.5 \times 22.5 = 213.75 \text{ in}^2 \]

  3. Calculate \( wh \): \[ wh = 16 \times 22.5 = 360 \text{ in}^2 \]

Now, plug these values into the surface area formula: \[ \text{Surface Area} = 2(152 + 213.75 + 360) \]

  1. Calculate the sum \( (lw + lh + wh) \): \[ lw + lh + wh = 152 + 213.75 + 360 = 725.75 \text{ in}^2 \]

  2. Now multiply by 2: \[ \text{Surface Area} = 2 \times 725.75 = 1451.5 \text{ in}^2 \]

Thus, the surface area of the suitcase is: \[ \boxed{1,451.5 , \text{in}^2} \]