To find the surface area of a rectangular suitcase, we can use the formula for the surface area \( A \) of a rectangular prism:
\[ A = 2(lw + lh + wh) \]
Where \( l \) is the length, \( w \) is the width, and \( h \) is the height.
Given:
- Length \( l = 9.5 \) inches
- Width \( w = 16 \) inches
- Height \( h = 22.5 \) inches
Now we can substitute these values into the formula:
- Calculate \( lw \):
\[ lw = 9.5 \times 16 = 152 , \text{in}^2 \]
- Calculate \( lh \):
\[ lh = 9.5 \times 22.5 = 213.75 , \text{in}^2 \]
- Calculate \( wh \):
\[ wh = 16 \times 22.5 = 360 , \text{in}^2 \]
- Now, add these areas together:
\[ lw + lh + wh = 152 + 213.75 + 360 = 725.75 , \text{in}^2 \]
- Finally, multiply by 2 to get the surface area:
\[ A = 2 \times 725.75 = 1451.5 , \text{in}^2 \]
Thus, the surface area of the suitcase is:
1,451.5 in.² (or 1 comma 451 point 5 in. squared) is the correct response.
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