assume salt water density = 1029 kg/m^3
and g = 9.81 m/s^2
mass in salt water = 1029*.8*60
= 1000 * d * 60
d = .8 (1029/1000) = .8232 m
A cargo barge is loaded in a saltwater harbor for a trip up a freshwater river. If the rectangular barge is 3 m by 20 m and sits 0.8 m deep in the harbor, how deep will it sit in the river?
2 answers
No