Component of thrust up
= 400,000 sin 37 Newtons
Lift = 756,000 N perpendicular to course made good so
lift up component
= 756,000 cos 37 Newtons
so
m g
=9.81 m = 400,000sin37+756,000cos37
A cargo aircraft has taken off from a mountain. It is climbing at constant speed and at an angle of θ=37 above horizontal. The engines of the plane provide a thrust of F thrust =400kN and the wings provides a lift of F lift=756kN. Drag/air resistance is negligible so F thrust, F lift, and weight are the only acting forces. What is the mass of the cargo aircraft ?
1 answer