Let the side of the bottom square be x, and the height of the box, h.
The volume is x²h=45
or
h=45/x²
The total surface area (5 faces) is
S=x²+4(x*h)=x(x+4h)
Make a table of 3 columns, comprising x, h and S. The value of x could vary between 4 and 5 in 0.1 ft intervals.
A cardboard box with an open top and a square bottom is to have a volume of 45 ft3 . Use a table utility to determine the dimensions of the box to the nearest 0.1 foot that will minimize the amount of cardboard used to construct the box.
1 answer
1 answer