To determine the magnitude of the force the nucleus feels towards the electrons, we can use Coulomb's Law, which states that the force between two charged particles is given by:
F = (k * q1 * q2) / r^2
Where:
F = Force
k = Coulomb's constant (approximated as 9 × 10^9 N m^2/C^2)
q1, q2 = electric charges of the two particles
r = separation between the two particles
In this case, the electric charge of a carbon atom is neutral (zero), so we will only consider the force due to the positively charged nucleus towards the negatively charged electrons.
The equation becomes:
F = (k * q_nucleus * q_electrons) / r^2
Since q_nucleus is positive and q_electrons is negative, the force will be attractive.
Given that the separation between the nucleus and the electrons is 20 nm (which is 20 × 10^-9 m), we can proceed to calculate the force:
F = (9 × 10^9 N m^2/C^2 * q_nucleus * q_electrons) / (20 × 10^-9 m)^2
However, to proceed with the calculation, we need the values of q_nucleus and q_electrons, which represent the electric charges of the nucleus and the electrons, respectively. Without this information, it is not possible to determine the exact magnitude of the force.
A carbon atom's nucleus and its electrons become separated by 20nm. What is the magnitude of the force the nucleus feels towards the electrons in N? Assume the electrons remain together.
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