initial KE=workdonebyfriction+final PE
1/2 m v^2= mg*mu*cos14*85 + mg*85sin14
solve for v.
A car with engine trouble slides 85 meters up along a 14 degrees ramp before coming to a stop. If the coefficient of friction between the tires and the road is 0.9, what was the velocity of the car at the bottom of the ramp?
I get 32.43 meters / second
is this correct?
3 answers
can you explain how you derive that equation?
we haven't learned about potential energy yet? is there another way to solve this?