Vf = Vi + a t
Vf = 21.9*10^3/3600 + .89(3.7)
in meters/ second
right then it is at
x = 0 + 21.9*10^3/3600 * 3.7 + (1/2)(.89)(3.7)^2
in meters
divide by 1000 for km
after that it continues at Vf forever and travels an additional distance d
d = Vf t
remember to divide by 1000 to get km again
A car with an initial speed of 21.9 km/h accelerates at a uniform rate of 0.89 m/s
2
for 3.7
s.
Find the final speed of the car.
Find the displacement of the car after that time.
Answer in units of km
1 answer