A car with a velocity of 19 m/s is accelerated uniformly at the rate of 1.8 m/s2 for 6.8 s. What is its final velocity?

Answer 1

Vf=Vi+at
Vf=?
Vi=19 m/s
a=1.8 m/s^2
t=6.8

Vf is what are we are trying to find.

So, Vf=(19 m/s)+(1.8 m/s^2)x(6.8s)

Vf= 31.24 m/s

But because of significant figures, our final answer would be 31 m/s.