A car weighing 1.0 x 10^4N is parked on a 34 degree slope. The brakes fail and the car starts to slide down the hill. Assume no friction. Show your work, and determine a) the acceleration of the car, and b) after it has moved 28.0 m, how fast is it moving?

Answer 1

a. m*g = 1.0*10^4 N.
m = 1.0*10^4/g = 1.0*10^4/9.8 = 1020 kg.

Fp = 1.0*10^4*sin34 = 5592 N. = Force
parallel to the hill.

a = Fp/m = 5592/1020 = 5.48 m/s^2.

b. V^2 = Vo^2 + 2a*d = 0 + 10.96*28 = 307
V = 17.5 m/s.