centripetal sideways
m v^2/R
m = .8*1000/9.81 = 81.55 kg
v = 25 m/s
R = 150 meters
gravitational up from seat
m g = 800 N
A car travels around an unbanked highway curve (radius 0.15 km) at a constant speed of 25 m/s. What is the magnitude of the resultant force acting on the driver, who weighs 0.8kN?
2 answers
-Equation--> (mv^2)/r
-convert mass from .8kN to kg by time 1000N time 9.81m/^2=81.55kg
-convert radius from .15km to m by time 1000m=150m
-speed is given: v =25m/s
-now you have everything need to plug into the equation.
plug into the equation and you get340N
-If you wand in kN, do that by divide by1000N because 1kN=1000N and you will get .340kN
-convert mass from .8kN to kg by time 1000N time 9.81m/^2=81.55kg
-convert radius from .15km to m by time 1000m=150m
-speed is given: v =25m/s
-now you have everything need to plug into the equation.
plug into the equation and you get340N
-If you wand in kN, do that by divide by1000N because 1kN=1000N and you will get .340kN