Draw triangle PQR
QR/sin124° = PR/sin14° = 18/sin42°
A car travelled from town P to town Q on a bearing of 56 for 18km it then travel to another town R on a bearing if 200 if R is directly south of P calculate
a) Distance QR
b) Distance PR
2 answers
PQ = 18km[56o].
P = 180-56 = 124o.
R = 200-180 = 20o.
Q = 180-124-20 = 36o.
QR/sin124 = 18/sin20
QR = 44 km.
PR/sin36 = 18/sin20
PR = 31 km.
P = 180-56 = 124o.
R = 200-180 = 20o.
Q = 180-124-20 = 36o.
QR/sin124 = 18/sin20
QR = 44 km.
PR/sin36 = 18/sin20
PR = 31 km.