Asked by lisa
a car traveling on a straight road at 20 meters per second accelerates to 26 meters per second in 12 seconds. what is the total distance traveled by the car? please help!
Answers
Answered by
Reiny
I know that there are formulas in physics for this type of question, but I am not a physics teacher , so I will use standard Calculus
a = (v2 - v1)/(time2 - time1) = (26-20)/(12-0) = 6/12 = 1/2
since a = 1/2
v = (1/2)t + c
when t = 0, v = 20
20 = c
so v = (1/2)t + 20
then
d = (1/4)t^2 + 20t + k
at t=0 , d = k
at t = 12 , d = (1/4)(144) + 20(12) + k= 276+k
distance covered in that 12 seconds = 276k - k = 276 m
drwls or bobpursley could do it much easier.
a = (v2 - v1)/(time2 - time1) = (26-20)/(12-0) = 6/12 = 1/2
since a = 1/2
v = (1/2)t + c
when t = 0, v = 20
20 = c
so v = (1/2)t + 20
then
d = (1/4)t^2 + 20t + k
at t=0 , d = k
at t = 12 , d = (1/4)(144) + 20(12) + k= 276+k
distance covered in that 12 seconds = 276k - k = 276 m
drwls or bobpursley could do it much easier.
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