A car traveling at2.24m/s skids and stops in

Question

2.55s determine the skidding distance of car

Answer 1

Acceleration
= (vf-vi)/t
= -2.24/2.55
= -0.8784 m/s

Δx = vi*t + (1/2)at²
=2.24(2.55)+(1/2)(-0.8784)(2.55²)
= 2.85 m