A car traveling at 91.0 km/h approaches the turnoff for a restaurant 30.0 m ahead. If the driver slams on the brakes with an acceleration of -6.40 m/s^2, what will her stopping distance be?

Answer 1

The stopping distance can be calculated using the equation d = (v^2)/(2a), where d is the stopping distance, v is the initial velocity, and a is the acceleration. Plugging in the given values, we get d = (91.0 km/h)^2/(2(-6.40 m/s^2)) = 5,837.5 m.