a car traveling at 43m/s decelerates at a rate of 7.1 m/s squared. how long did it take the car to stop? what distance did the car travel while stopping?

Answer 1

v = Vi -7.1 t
0 = 43 - 7.1 t
t = 43/7.1 = 6.06 s

average speed during stop = 7.1 /2
=3.55 m/s

d = 3.55 * 6.06 = 21.5 m