a car traveled at uniform velocity of 20m/sec for 5 sec the brakes are applied and car s uniformly and come to rest in further 8 sec.find

Question

a)distance traveled in first five sec
b)distance traveled after breaks are applied
c)total displacement during this period and its avrage velocity in whole journy.

Answer 1

(a) s1 =v•t =20•5 =100 m,
(b)
v(final) =v - a•t
v(final) =0
a =v/t,
s =v•t - at²/2 =
= v•t - v•t²/2•t =v•t/2=20•8/2=80 m
(c)
s =s1+s2 = 100+80 = 180 m
(d)
v(ave) = s/t =180/(8+5) = 13.85 m/s.

Answer 2

Kch nahi