A car travel a distance of 8 km frome P to Q then moves 6 km at right angles to PQ .Find its travel distance and displacement

Answer 1

3 , 4 , 5 right triangle so distance = 10
If 8 in the x direction and then 6 in the y direction then
tan A = 6/8 = 3/4 where A is angle above x axis
A = 37 degrees approximately

Answer 2

d = 8 + 6 = 14 km = Travel distance.

D^2 = 8^2 + 6^2 = 100,
D = 10 km @ 37o. = Displacement = Straight line distance from starting point.