a. d1 = 0.5a*t^2 = 0.5*1.3*5.9^2=22.63 m
V1 = a*t = 1.3 * 5.9 = 7.67 m/s.
V = V1 + a*t = 7.67 - 1.7*1.6 = 4.95 m/s
b. d1 = 0.5a*t^2 = 0.5*1.3*5.9^2=22.63 m
d2 = (V^2-V1^2/2a =
(4.95^2-(7.67^2))/-3.4 = 10.1 m.
d = d1+d2 = 22.63 + 10.1 = 32.73 m
A car starts from rest and travels for 5.9 s with a uniform acceleration of +1.3 m/s2. The driver then applies the brakes, causing a uniform acceleration of -1.7 m/s2. The breaks are applied for 1.60 s.
(a) How fast is the car going at the end of the braking period?
2.6
m/s
(b) How far has the car gone from its start?
M
1 answer