A car starts from rest and travels for 5.10 s with a uniform acceleration of +1.40 m/s2. The driver then applies the brakes, causing a uniform acceleration of -2.01 m/s2. If the brakes are applied for 2.83 s, how fast is the car going at the end of the braking period?

Answer 1

part 1: v = 0+at = 1.40 * 5.10 = 7.14 m/s
part 2: v = 7.14 + at = 7.14 - 2.01*2.83 = 1.45 m/s

Answer 2

Part A.) 1.45m/s
Part B.) 30.4 m