A car starts from rest and moves along x-axis with constant acceleration (5m/secondsquare) fr 8 sec. If it then countinues with constant velocity. What distance will the car cover in 12 sec since it started frm rest. plz anybody explain me u gave me explaination before also bt it ws no enough plz tell me the answers also.
4 answers
I think the answer is 360m is it correct experts
acceleration period:
v = a t = 5 * 8 = 40 m/s
x = (1/2) a t^2 = 2.5 * 64 = 160 m
this is the initial condition for the constant velocity coasting period:
x = Xi + Vi t + (1/2) a t^2
x = 160 + 40 t + (1/2) 0 t^2
= 160 + 40(12-8)
= 160 + 160
= 320 meters
v = a t = 5 * 8 = 40 m/s
x = (1/2) a t^2 = 2.5 * 64 = 160 m
this is the initial condition for the constant velocity coasting period:
x = Xi + Vi t + (1/2) a t^2
x = 160 + 40 t + (1/2) 0 t^2
= 160 + 40(12-8)
= 160 + 160
= 320 meters
tnx Mr. Damon
bt i don't think the explaination is fr a class 9th student cn it be mr easy?? as i don't know what is Xi and Vit
bt i don't think the explaination is fr a class 9th student cn it be mr easy?? as i don't know what is Xi and Vit
I gt it Mr. Damon
tnxx buddy
tnxx buddy
3 answers