In this situraion,
Vf = sqrt(2aX) where
Vf = the final velocity, 8 ft/s
X = the distance traveled, 250 ft
Solve for the acceleration, a, in ft/s^2.
A car starts from rest and accelerates uniformly to a velocity of 8ft/s after traveling 250 ft. Find its acceleretaion.
Help me with this pleeaase.
Thank you.
3 answers
i don't get it
What don't you get? The derivation of the first formula or how to solve it for a?
Here is how to derive the first formula.
Vf = a t
X = (1/2) a t^2
Vf^2 = a^2 t^2 = 2 a X
Vf = sqrt(2 a X)
Here is how to derive the first formula.
Vf = a t
X = (1/2) a t^2
Vf^2 = a^2 t^2 = 2 a X
Vf = sqrt(2 a X)