A car starts from rest accelerate uniformly until it reaches a velocity of 30m/s after 5s.it traves with uniform velocity for 15s and is being brought to rest in 10 with a uniform retardation.dEtermine the following (a) the acceleration of the car.(b) the retardation. (c) the distance covered after 5s.(d) the total distance covered.

Answer 1

a) & b)
v = at
solve for a
c) x = 1/2 at^2
d) middle:
x = vt
slowing
x = vt- 1/2 at^2

Answer 2

Velocity =30/5=6m/s, retardation =30/10=3m/s, distance=30x5=150m, distance = 30x30 =900m

Answer 3

A car start from a rest and accelerate uniformly until it reaches a velocity of 30m/ s after 5