if the town square is at x = 0 and east is positive then:
x = -200 + 15 t
in ten minutes x = -200 + 150 = -50 or 50 meters west of the square
when is x = 0?
0 = -200 + 15 t
t = 200/15 = 13 1/3 seconds to the square
A car starts 200 m west of the town square and moves with a constant velocity of 15 m/s toward the east.
a.Write the equation that represents the motion of the car.
b.Where will the car be 10 minutes later?
c.When will the car reach the town square?
3 answers
Ok so I’m not going to do the whole question over again but here’s what I have:
(200m) / (15m/s) = 13.33333 sec
As far as where the car is after 10mins, my ANSWER KEY says *8800m* but I seem to keep getting 9000m.
Ex. (Vi + Vf) t
/2
[excuse my inability to format this, and I’m too lazy to put in units]
First, 10min = 600sec (t)
(15+15)= 30
30/2 = 15
15 x 600 = 9000m
But whatever lol. I hope this helped in some way.
(200m) / (15m/s) = 13.33333 sec
As far as where the car is after 10mins, my ANSWER KEY says *8800m* but I seem to keep getting 9000m.
Ex. (Vi + Vf) t
/2
[excuse my inability to format this, and I’m too lazy to put in units]
First, 10min = 600sec (t)
(15+15)= 30
30/2 = 15
15 x 600 = 9000m
But whatever lol. I hope this helped in some way.
I just wanted to add onto what Kat said- I also kept getting 9000, but since you start at -200m, I subtracted 200m from the 9000m to get the 8800m. I think that's how you're supposed to do it. :)
3 answers