A car runs at a constant velocity of 15m/s for 300sec and then accelerates uniformly to a velocity of 25m/s over a period of 20s. This velocity is mantained for 300s before the car is brought to rest with uniform deceleratiom in 30s. Draw a velocity time graph to represent the journey described above.
2 answers
I need an answer
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a) the acceleration while the velocity changes from 15m/s to 25m/s
Solution
a=∆v/∆t=V2-V1/t2-t1
=25-15/320-300=10/20
1/2m/s or 0.5m/s
b) total distanced travelled
Solution
L×B + ½(a+b)h + L×B + ½b×h
300×15 + ½(15+25)20 + 300×25 + ½×30×25
4500 + 400 + 7500 + 375
=12775m
C) Average speed = total distanced cover/time taking
=12775/650
19.6m/s
a) the acceleration while the velocity changes from 15m/s to 25m/s
Solution
a=∆v/∆t=V2-V1/t2-t1
=25-15/320-300=10/20
1/2m/s or 0.5m/s
b) total distanced travelled
Solution
L×B + ½(a+b)h + L×B + ½b×h
300×15 + ½(15+25)20 + 300×25 + ½×30×25
4500 + 400 + 7500 + 375
=12775m
C) Average speed = total distanced cover/time taking
=12775/650
19.6m/s
1 answer