A car passed a point on a course at exactly 12 noon and maintained a speed of 60 km/h. A second car passed the same point 1 hour later, followed the same course, and maintained a speed of 100km/h. When, and after what distance from this point, would the second car have caught up to the first car?

Answer 1

time passed since the second car passed the check point ---- t hours
distance covered by first car = 60 + 60t
distance covered by the 2nd car = 100t

they are equal, take it from there

Answer 2

Thank you, Reiny.

Answer 3

d1 = d2,
60 * T = 100 *(T-1),
60T = 100T - 100,
T = 2.5 h.

d = 60*T = 60*2.5 = 150 km.