If it is going up at constant speed, then
pushing force-gravityforce-friction=0
pushing force=mgSinTheta+600N
That is the net pushing force on the car
A car of weight 1.4*10^4N is moving up an incline at a constant speed of 6.2 m/s . The incline makes an angle of 5.0 to the horizontal. A frictional force of 600 N acts on the car in opposite direction. State the net force of the car
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