A car of mass 720 kg travels round a horizontal, semicircular racetrack of radius 200 m, at a constant speed of 48 km/h. What is the sideways component of the force exerted by the track on the car’s tyres?

Answer 1

F = m v^2/r
where
m = 720
v = 48000/3600 = 13.33 m/s
r = 200