A car of mass 1670 kg is traveling without slipping on a flat, curved road with a radius of curvature of 34 m. If the car's speed is 14 m/s, what is the frictional force between the road and the tires?

Answer 1

It is the centripetal force, M V^2/R.

I get 8610 Newtons

Answer 2

F(fr) = m•a = m•v²/R =
=1670•(14)²/34 =9627 N