A car of mass 1390 kg rests on a hydraulic lift with a piston of radius 0.26 m that is connected to a second piston of radius 0.033 m. If the car is just barely lifted off the ground, what is the force at the second piston?
I Tried
F1/F2 = r1^2 / r2^2
==> 1390x10 / F2 = 0.26^2 / 0.033^2 then I calculated F2 and found 223.92N but it didn't work.. Help please
2 answers