KE = m•v^2/2 = Q = C•Δt ,
Δt = m•v^2/2•C = 1250•(17)^2/2•10000 =18 degr
A car of mass 1.25 103 kg is initially moving on a level road at a speed of 17.0 m/s. Compute the increase in temperature of the brakes, assuming that all the mechanical energy ends up as internal energy in the brake system. Assume a total heat capacity of 10,000 J/C°.
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