a = 0.0235 m/s^2.
t = 67.8 s.
d = 1km = 1,000 m.
d = Vo*t + 0.5a*t^2 = 1,000 m.
Vo*67.8 + 0.5*0.0235*67.8^2 = 1000
67.8Vo + 54 = 1000
67.8Vo = 1000-54 = 945.99
Vo = 14 m/s.
A car, moving along a straight stretch of highway, begins to accelerate at 0.0235 m/s
2
It
takes the car 67.8 s to cover 1 km.How fast was the car going when it first
began to accelerate?
1 answer