d=vi*t+1/2 a t^2
1=vi*48.6+.01305(48.6)^2
solve for vi
A car, moving along a straight stretch of highway, begins to accelerate at 0.0261 m/s2. It takes the car 48.6 s to cover 1 km.
How fast was the car going when it first
began to accelerate?
Answer in units of m/s
Couldn't find a formula for this :(
1 answer