v = Vi + a t
d = Vi t + (1/2) a t^2
so
1000 = Vi (23.2) + .007(23.2)^2
solve for Vi
A car, moving along a straight stretch of high- way, begins to accelerate at 0.014 m/s2. It takes the car 23.2 s to cover 1 km.
How fast was the car going when it first began to accelerate?
Answer in units of m/s.
1 answer