A car moves uniformly at a rate of 10 m/s square from an initial velocity of 18 km /h for 30 sec. Find the distance covered during this period ?

3 answers

Answer the question
u = 18,000 m / 3600 s + 10 t = 5 +10 t
x = u initial t + (1/2) a t^2 = 5 (30) + (1/2)(10)(30)^2
= 150 + 5 * 900
I am expecting a raise by the way.