A car, mass - 1950 kg, accelerates at +2.33 m/s (squared). Find the magnitude of the normal force acting on the car. If later, when the car is cruising at 26.5 m/s, the driver applies a force of magnitude 10,000 N to stop the car. What is the distance it takes for the car to come to a stop.

Question

A car, mass - 1950 kg, accelerates at +2.33 m/s (squared).  Find the magnitude of the normal force acting on the car.  If later, when the car is cruising at 26.5 m/s, the driver applies a force of magnitude 10,000 N to stop the car.  What is the distance it takes for the car to come to a stop.

drwls · Answer

On level ground, the "normal force" is the weight, M*g. The force accelerating the car is M*a. It is not clear what they mean by "normal".

For the stopping distance X,
(stopping force)*X = initial kinetic energy

Marshall · Answer

normal reaction=m*g 9.81*1950=19129,5newtons using the equation of motion:s=[(v^2)-(u^2)]/2a 4,66s=702,25 thus s=150,7m