A car (m = 610.0 kg) accelerates uniformly from rest up an inclined road which rises uniformly, to a height, h = 49.0 m. Find the average power the engine must deliver to reach a speed of 24.7 m/s at the top of the hill in 20.5 s(NEGLECT frictional losses: air and rolling, ...)

Answer 1

m g h + (1/2) m v^2 = energy gain during trip

= 610 * 9.81 * 49 + (1/2) * 610 * 24.7^2 in Joules

divide that energy gain by 20.5 seconds to get Watts