A car (m = 1870 kg) is parked on a road that rises 12.1 ° above the horizontal. What are the magnitudes of (a) the normal force and (b) the static frictional force that the ground exerts on the tires?

Answer 1

M*g = 1870 * 9.8 = 18,326 N.=Wt. of car.

Fp = 18,326*sin12.1 = 3841 N.

a. Fn = 18,326*Cos12.1=17,919 N.= Normal.

b. Fp-Fs = M*a.
3841-Fs = 1870*0 = 0.
Fs = 3841 N. = Force of static friction.