h = 0.5g*Tf^2 = 21.3-1.8 = 19.5 m
4.9*Tf^2 = 19.5,
Tf^2 = 3.98, Tf = 1.99 s. = Fall
time.
a. d = Xo * Tf = Xo * 1.99 = 61,
Xo = 30.6 m/s = Hor. velocity at time it leaves the road.
A car is traveling on a level horizontal rode comes to a bridge during a storm and finds the bridge washed out. The driver must get to the other side, so he decides to try leaping it with his car. The side of the road the car is on 21.3m above the river, while the opposite side is mere 1.8m above the river. The rive itself is a ranging torrent 61.0m wide. How fast should the car be traveling at the time it leaves the road in order just to clear the river and the land safely on the opposite side?. What is the speed of the car just before it lands on the other side?
2 answers
b. V^2 = Vo^2 + 2g*h.
V^2 - 0 + 19.6*19.5 = 382.2,
V = 19.5 m/s.
V^2 - 0 + 19.6*19.5 = 382.2,
V = 19.5 m/s.
1 answer