A car is traveling at a speed of 15 m/s, slams on the brakes, locking the wheel of the car. The coefficient of kinetic friction between the tires and the road is 0.64. What is the speed of the vehicle after 2 seconds have passed?

Answer 1

Coefficient of kinetic friction =F/R=ma/mg
Which is a/g since the mass is equal
0.64=a/10 a=6.4m/s
NB. g=10m/s
Recall v=u+at
V=15+6.4×2
V-15=12.8
V=12.8+15
V=27.8m/s