Asked by larry

A car is traveling at a constant speed of 31.8 m/s on a highway. At the instant this car passes an entrance ramp, a second car enters the highway from the ramp. The second car starts from rest and has a constant acceleration. What acceleration must it maintain, so that the two cars meet for the first time at the next exit, which is 2.58 km away?

Answers

Answered by Steve
It takes 2580/31.8 = 81.13 seconds for car 1 to get to the exit.

So, for car 2,
1/2 a*81.13^2 = 2580
just solve for a.
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