It takes 2580/31.8 = 81.13 seconds for car 1 to get to the exit.
So, for car 2,
1/2 a*81.13^2 = 2580
just solve for a.
A car is traveling at a constant speed of 31.8 m/s on a highway. At the instant this car passes an entrance ramp, a second car enters the highway from the ramp. The second car starts from rest and has a constant acceleration. What acceleration must it maintain, so that the two cars meet for the first time at the next exit, which is 2.58 km away?
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