A car is traveling 30 m/s undergoes a constant negative acceleration of magnitude to meters per second squared when the brakes are applied how many revolutions does each tire make before the car comes to stop assuming that the car does not get on the tires have radius of 30 cm
2 answers
try again, this time providing the missing numbers, and constructing sentences that make sense.
v = Vi + a t
here Vi = 30 and a = -2 m/s^2 (I guess)
so v = 30 - 2 t
so when v = 0, stopped
t = 15 seconds
how far did it go?
x = Vi t + (1/2)at^2 = 30 (15) - 1 * 225 = 225 meters
or another way average speed during meltdown = 15 m/s for 15 seconds
so 15*15 = 225 again
tire circumference = 2 pi R = 2 pi * 0.30
revolutions = 225 / circumferrence
here Vi = 30 and a = -2 m/s^2 (I guess)
so v = 30 - 2 t
so when v = 0, stopped
t = 15 seconds
how far did it go?
x = Vi t + (1/2)at^2 = 30 (15) - 1 * 225 = 225 meters
or another way average speed during meltdown = 15 m/s for 15 seconds
so 15*15 = 225 again
tire circumference = 2 pi R = 2 pi * 0.30
revolutions = 225 / circumferrence
1 answer