We can use the following formula to solve this problem:
centripetal force = mv^2/r
where m is the mass of the car, v is its speed, and r is the radius of the curve.
In this case, the centripetal force is provided by the horizontal component of the normal force, since there is no friction. So we can write:
centripetal force = N sin(θ)
where N is the normal force and θ is the angle of banking.
Equating these two expressions for the centripetal force, we get:
N sin(θ) = mv^2/r
Solving for θ, we get:
θ = sin^-1(mv^2/(Nr))
Substituting the given values, we get:
θ = sin^-1((900 kg)(40.0 m/s)^2/((900 kg)(9.81 m/s^2)(100m)))
θ ≈ 32.83 degrees
Therefore, the angle θ has to be approximately 32.83 degrees if the road is frictionless.
A car is moving in curved bank ,the 900kg car is moving at speed of 40.0 m/s through
this curve of radius 100m.what does the angle θ has to be if the road is frictionless.
1 answer