To determine the acceleration of the car, we can use the formula for uniform (constant) acceleration, which is given by:
\[ a = \frac{\Delta v}{\Delta t} \]
where:
- \( \Delta v \) is the change in velocity
- \( \Delta t \) is the change in time
In this problem:
- The initial velocity (\( v_i \)) is 25.0 m/s.
- The final velocity (\( v_f \)) is 0 m/s (since the car comes to a complete stop).
- The time (\( \Delta t \)) is 15.7 seconds.
First, calculate the change in velocity (\( \Delta v \)):
\[ \Delta v = v_f - v_i = 0 \, \text{m/s} - 25.0 \, \text{m/s} = -25.0 \, \text{m/s} \]
Now, plug the values into the acceleration formula:
\[ a = \frac{\Delta v}{\Delta t} = \frac{-25.0 \, \text{m/s}}{15.7 \, \text{s}} \approx -1.59 \, \text{m/s}^2 \]
Therefore, the acceleration of the car is approximately \( -1.59 \, \text{m/s}^2 \). The negative sign indicates that the car is decelerating.
a car in motion, accelerates uniformly from 25.0 m/s to a complete stop over 15.7s. What is the acceleration of the car?
a=[?] m/s^2
1 answer