The weight and kinetic friction forces on the tires will be different unless the center of mass is midway between the tires. I assume they want you to assume that it is, so that 1/4 of the total frioction force is on each tire.
In that case,
4*Ftire* X -Fwind*X= (1/2)M Vo^2
Solve for Ftire. X = 10 m
The equation says that the work done against sliding friction and the wind equals the initial kinetic energy. The wind work is negative since it comes from behind.
A car has an initial speed of 23.0 ms-1. In addition, there is also wind blowing in direction similar to the car with a force of 30 N. If the brakes are applied and the car skidded for 10 meters before coming to a halt, determine the kinetic friction of one of the car’s tyre and the road.
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