KE(rot)=Iω²/2 =MR²ω²/2•2
KE(tr)=0.25•KE(rot)
KE(tr)=0.25•MR²ω²/4
mv²/2 = MR²ω²/16
v=(Rω/4)•sqrt{2M/m)=4.5 m/s
C. 4.5 m/s
A car has a flywheel ( a diks of R=0.2m and uniformly distributed mass M=100kg) that can convert 25% of the rotational kinetic energy into translational kinetic energy. The mass of the car is 1000kg ( including flywheel). Suppose the car is at rest, and the flywheel has a angular speed of 200 rad/s. After all the rotational energy is converted to kinetic energy of the car, what is the speed of the car? Ignore air resistance.
A. 0 m/s; B. 3 m/s; C. 4.5 m/s; D. 9 m/s. Thanks for your help.
1 answer
1 answer