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A car drives down a road in such a way that its velocity ( in m/s) at time t (seconds) is

v(t)=2t^1/2 +2 .
Find the car's average velocity (in m/s) between t=4 and t=9.

i really need help with thisss

1 answer

V(4) = 2 * sqrt(4) + 2 = 4 + 2 = 6m/s.

V(9) = 2 * sqrt(9) + 2 = 6 + 2 = 8.

V(avg.) = (6 + 8) / 2 = 7m/s.