A car coasts (engine off) up a 30 degree grade. If the speed of the car is 25m/s at the bottom of the grade, what is the distance traveled by the car before it comes to rest?

Answer 1

m•a=m•g•sinα
a=g•sinα
s=v²/2•a=
= v²/2•g•sinα=
=25²/2•9.8•0.5=
=63.78 m

Answer 2

Where did the Sin(A) come from