A car begins at rest at t0 = 0. The car starts moving and finally covers a distance d = 617 m in a time tf = 105 s. In a coordinate system with north being the positive x-direction, the car's motion is in the southern direction. What was the car's average speed during this period, in meters per second?.

Answer 1

average velocity = -617/105
= -5.88 m/s
and
average speed = 5.88 m/s
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in anticipation of a part B:
x = Xi + Vi t + (1/2) a t^2

-617 = 0 + 0 t + (1/2)a (105)^2

a = -1234/105^2

a = - .112 m/s^2